Show that if a, b, c ER then: (a) a−b=-(b-a). (b) (a + b)(ab) - a(a - b) + b(b-a) = 0. (c) a b=0⇒a=0 o b=0. (d) (-a)(cd) = ad - ac.
Show that if a, b, c ER then: (a) a−b=-(b-a). (b) (a + b)(ab) - a(a - b) + b(b-a) = 0. (c) a b=0⇒a=0 o b=0. (d) (-a)(cd) = ad - ac.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.1: Real Numbers
Problem 29E
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![段階的に解決し、 人工知能を使用せず、 優れた仕事を行います
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Show that if a, b, c ER then:
(a) a-b=-(b-a).
(b) (a+b)(a-b)-a(a-b)+b(b-a) = 0.
(c) a.b=0⇔a=0o6=0.
(d) (-a)(c-d) = ad-ac.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F39cdee93-e28a-4e21-8715-0dbf90412314%2F562653ce-9ebe-483a-b8eb-954c82ae374d%2Ft5ql1if_processed.jpeg&w=3840&q=75)
Transcribed Image Text:段階的に解決し、 人工知能を使用せず、 優れた仕事を行います
ご支援ありがとうございました
SOLVE STEP BY STEP IN DIGITAL FORMAT
DON'T USE AI | DON'T USE AI DON'T USE AI DON'T USE AI
Show that if a, b, c ER then:
(a) a-b=-(b-a).
(b) (a+b)(a-b)-a(a-b)+b(b-a) = 0.
(c) a.b=0⇔a=0o6=0.
(d) (-a)(c-d) = ad-ac.
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