Show that the differential equation x²y³ + x(1+y²)y' = 0 is not exact, but becomes exact when multiplied by the integrating factor 1 μ(x, y) Then solve the equation. = xy ³* The given equation is not exact, because My = which is different from N = After multiplication with u(x, y), the equation is exact, because then My = Nx = The general solution of the differential equation is given implicitly by = c, for any constant c, where y > 0.

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