Show that the language, L = {0™1" | m # n}, is not regular, following the steps below. %3D In class, we showed that the language L' = {0*1* | i > 0} is not regular by applying the Pumpling Lemma for regular languages. %3D (a) For any two languages, L1 and L2, say over {0, 1}, their difference L1 – L2, is the set of all strings that are in L1 but not in L2. Express L' as the difference of a suitably chosen regular language and L.

Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
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Chapter1: Computer Networks And The Internet
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Qn.3 Show that the language, L = {0™1" | m # n}, is not regular, following the steps below.
In class, we showed that the language L' = {0ʻ1² | i > 0} is not regular by applying the
Pumpling Lemma for regular languages.
(a) For any two languages, L1 and L2, say over {0, 1}, their difference L1 – L2, is the set of
all strings that are in L1 but not in L2.
Express L' as the difference of a suitably chosen regular language and L.
Transcribed Image Text:Qn.3 Show that the language, L = {0™1" | m # n}, is not regular, following the steps below. In class, we showed that the language L' = {0ʻ1² | i > 0} is not regular by applying the Pumpling Lemma for regular languages. (a) For any two languages, L1 and L2, say over {0, 1}, their difference L1 – L2, is the set of all strings that are in L1 but not in L2. Express L' as the difference of a suitably chosen regular language and L.
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