Show that Z,[V3] = {a + bV3| a, b E Z,} is a field. For any positive integer k and any prime p, determine a necessary and suf- ficient condition for Z,[Vk] = {a + bVk|a, b E Z,} to be a field.

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter6: More On Rings
Section6.3: The Characteristic Of A Ring
Problem 18E
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Show that Z,[V3] = {a + bV3| a, b E Z,} is a field. For any
positive integer k and any prime p, determine a necessary and suf-
ficient condition for Z,[Vk] = {a + bVk|a, b E Z,} to be a field.
Transcribed Image Text:Show that Z,[V3] = {a + bV3| a, b E Z,} is a field. For any positive integer k and any prime p, determine a necessary and suf- ficient condition for Z,[Vk] = {a + bVk|a, b E Z,} to be a field.
Expert Solution
Step 1

We need to show that Z73=a+b3 a,bZ7 is a field.

To show that Z7[3] is a field, we need to verify the following:

  1. Z7[3] is a commutative ring with identity.

  2. Every nonzero element in Z7[3] has a multiplicative inverse.

  3. To show that Z7[3] is a commutative ring with identity, we need to show that it satisfies the following axioms:

  • Addition is commutative and associative.
  • There exists an additive identity element 0.
  • Every element has an additive inverse.
  • Multiplication is commutative and associative.
  • There exists a multiplicative identity element 1.
  • Every nonzero element has a multiplicative inverse. It is straightforward to verify that Z7[3] satisfies all these axioms.
Step 2

To show that every nonzero element in Z7[3] has a multiplicative inverse, we need to show that for any nonzero element a + b3 in Z7[3], there exists an element c + d3 in Z7[3] such that (a + b3)(c + d3) = 1. This can be done by solving the equation(a + b3)(c + d3) = 1 for c and d. We get c = (a4) + (3b4) and d = (3a4) + (b4), where the division is taken in Z7. It can be verified that these values of c and d satisfy the equation, and hence every nonzero element in Z7[3] has a multiplicative inverse.

Therefore, Z7[3] is a field.

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