Simplify the following Boolean expressions i) ii) x.x + x.x' (x + y). (x + y') iii) x.y+x.y.z iv) x. (y + x') +y v) (x +y). (xy + xy') +xy +y

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Q: the distributive law (x+y)(x’+y) = xx’+xy+yx’+yy = y

A: the distributive law (x+y)(x’+y) = xx’+xy+yx’+yy = y .

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Q: Problem_#02] Using Boolean algebra techniques, simplify the expressions below. (a) (A + B)(A + C)…

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