sin 0 in 0 Show that the following statement is an identity by transforming the left side into the right side. sin e (sec e + csc e) = tan e + 1 We begin by writing the left side in terms of sin e and cos e. We can then perform the multiplication and simplify in terms of tan 0. 1 of sin e (sec e + csc e) = sin e sin 0 sin e sin e sin e sin e = tan e + 1

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section: Chapter Questions
Problem 16RE
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Show that the following statement is an identity by transforming the left side into the right side.
sin e (sec e + csc e) = tan e + 1
We begin by writing the left side in terms of sin e and cos e. We can then perform the multiplication and simplify in terms of tan e.
1
1
sin e (sec e + csc 0) = sin e
sin 0
sin 0
sin e
sin 0
sin e
sin e
sin e
= tan e + 1
Because we have succeeded in transforming the left side into the right side, we have shown that the statement sin e (sec e + csc 0) = tan e + 1 is an identity.
Transcribed Image Text:Show that the following statement is an identity by transforming the left side into the right side. sin e (sec e + csc e) = tan e + 1 We begin by writing the left side in terms of sin e and cos e. We can then perform the multiplication and simplify in terms of tan e. 1 1 sin e (sec e + csc 0) = sin e sin 0 sin 0 sin e sin 0 sin e sin e sin e = tan e + 1 Because we have succeeded in transforming the left side into the right side, we have shown that the statement sin e (sec e + csc 0) = tan e + 1 is an identity.
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