sin 2h sin 3h lim h2

Q: sin(2x) lim x→0 sin(7x)

A: This is infinity/infinity form, apply L-Hospital rule to proceed further.

Q: sin 9h lim h→0 h

A:

Q: Find the limit

A: Consider the limit, First of all, apply the fraction rule, Then,

Q: lim エ→ミ e2: 1+ tan lim r エー sec x

A: limx→z z3e2z=z3e2z (The function is independent of x.)

Q: Find the limits

A:

Q: Evaluate the limit.

A: Given limit: limh→0 sin2h sin3hh2

Q: sin(a+x)-sin x limx→o

A:

Q: sin (7 + h) - 81. lim h→0 s h

A: Since you have asked  multiple questions in single request  so we  will be answering only first…

Q: sin 0 lim 0-0 sin 20

A: To evaluate:limθ→0sin(θ)sin(2θ) Solution: limθ→0sin(θ)sin(2θ) On simplifying further we get:…

Q: tan 0 (2) Lim = 1 %3D

A: We first expand the series of tan x and then proceed as explained below:

Q: lim x² sin(x²) .2

A:

Q: Find the limit

A:

Q: Find the limit

A: We have to evaluate

Q: sin 5x lim X→0 sin 4x

A: To find the limit: limx→0sin5xsin4x Solution: Quotient rule of differentiation states that:…

Q: sin a 4. lim I 1+ cos3 x

A:

Q: lim (cot2 x x2 3/2 2/3 -2/3

A:

Q: lim 2 sin(-2 x) 0.3) 4 sin (5 x)

A:

Q: cos h -1 lim h

A:

Q: sin 4. lim

A: problem is solved using L'hopital rule

Q: Find the limits

A:

Q: c. lim_sin x x- a. lim sin x %3D

A: We know that for any given functiony=fx, at x=a limit will exist if limx→a-fx=limx→a+fx

Q: Use the shown table to find the indicated shown limit.

A: The given expression is limx→0sin3xx

Q: lim cos x→1 х — 1

A: Given, limx→1cos x2-1x-1

Q: lim 1-e*) X-0 x sin x

A:

Q: lim Ht cos

A:

Q: lim 2 Sin

A:

Q: sin(x ²–4) -4) lim x+2) tan (x+2) x→-2

A: Rearrange the expression than Apply the limit and simplify.

Q: Sin 10. Im sin ax 12.lim X-0 sinbr X-0

A: We have to find

Q: () lim x→0 .2 x cos

A: We have to find the limit: limx→0x2cos1x After putting limit value, limx→0x2cos1x=0×cos10 Since 10…

Q: sin (a+h) – sin a lim h→0 h

A: Applying the limit: limh→0sina+h-sinah=sina+0-sina0=sina-sina0=00 This is of the form 0/0.…

Q: sin(3r) sin(2r) x sin(5x) (e) lim

A:

Q: lim θ→0  sin θ 9θ + tan θ

A: GIVENlimx→0 sin θ9θ+tanθ

Q: lim 4 sin(x + n) +3

A: We can split the limit expression using the sum of limits rule, limx→afx+gx=limx→afx+limx→agx The…

Q: lim 6 sin(x + sin(x))

A:

Q: 2 sin(z) – sin(2z) lim -10 z- sin(z)

A: We use L'Hospital rule to solve this limit problem.

Q: sin (3t) (d) lim 1-0 sin (8t) sin (x-4) (е) lim x→4 х—4 cos (2z)-1 (f) lim-

A:

Q: sin (1 cos x) sin x -0" sin Vx sin (x2 + x) 25. lim 26. lim sin (sin x) 27. lim 28. lim sin (x - 4)…

A:

Q: sin(x-1) lim sin æ? –1 x→1

A:

Q: (а) lim h 1- e-h sin x (b) lim

A: a). limh→01-e-hh=limh→01-1ehh=limh→0eh-1h·eh=limh→0eh-1h·limh→01eh=1·1e0…

Q: sin x - C cos 2 29. lim * - sin æ

A: We use l Hospital's Rule

Q: evaluate the limit.

A:

Q: sin4x 15. lim x→0 sin7x

A:

Q: sin 0 (a) lim- 0→0 60 sin (6r

A: Since you have asked multiple question, we will solve the first question for you as per our guide…

Q: Evaluate the limits.

A: As per the bartleby guidelines for more than one part only only one has to be solved. Please upload…

Q: 03 sin- find lim 0→0 sin 02

A:

Q: sin(2x) – sin (2a) Find lim x-0 x - a

A: we have to find  limit

Q: 10 sin(0-5) Find lim 0-5 02-20–15

A: