Question
Asked Sep 18, 2019
sin (7x
The function y
1) is a composition, and so we must use the Chain Rule, given below, to find the
=
derivative
[f(g(x))] f (g(x))g'(x)
dx
For the given function sin-2(7x + 1), the "inside" function is 7x
1 and the "outside" function is
f(x)
=
X
help_outline

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sin (7x The function y 1) is a composition, and so we must use the Chain Rule, given below, to find the = derivative [f(g(x))] f (g(x))g'(x) dx For the given function sin-2(7x + 1), the "inside" function is 7x 1 and the "outside" function is f(x) = X

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check_circleExpert Solution
Step 1
[f(g(x)]- (8(x)s '(x)
dx
f(g(x))sin(7x+1)
f(g(x) sin((x))
f(x)= sinx)
help_outline

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[f(g(x)]- (8(x)s '(x) dx f(g(x))sin(7x+1) f(g(x) sin((x)) f(x)= sinx)

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Math

Calculus