sin ( sin-1 ( pi/4 ) )   Can you show me how to simplify this expression? Thx!

Q: sin(2x) lim x→0 sin(7x)

A: This is infinity/infinity form, apply L-Hospital rule to proceed further.

Q: Find the limits

A:

Q: (sin -(x/ 10) dx Evaluate the integral 2 100 - x

A: Given: I=∫sin-1x102dx100-x2 for evaluating given integral, in given integral we substitute…

Q: sin 9x lim sin 7x

A: Given: L=limx→0sin9xsin7x We know that limx→0sinkxkx=1…

Q: 1+sinx 1-sinx The simplified form of 1-sinx 1+sinx is

A: simplification form :

Q: | Sin(3メ+5)dx

A: We have to find the indefinite integral

Q: True or false If cosh x = then sinh x=

A: We have cheek the statement

Q: sin²(x) + sin(x) dx To evaluate the using basic formula of integration (without using cos²(x)…

A:

Q: | sin 5x sin xdx

A:

Q: sin 5x 6. lim x→0 sin 10x

A:

Q: 6. sec (sin-1 x)

A: Interconversion

Q: sin - COS I Q1-Solve by hospital rule lim

A: By using L hospital rule

Q: sin(7x) lim x-0 sin(8x)

A: NOTE: Refresh your page if you can't see any equations. . use L'hospital's rule

Q: ∫〖sin〗^3 xdx

A: Consider the indefinite integral ∫sin3x dx. To solve this integral first rewrite the integrand using…

Q: sin(2x) – sin(x) = 0

A: sin 2x = 2 sin x cos x

Q: sin squared theta/2= csctheta-cottheta/2csctheta] verify with steps

A:

Q: sin-1 (0.8422)

A:

Q: sin 5x lim X→0 sin 4x

A: To find the limit: limx→0sin5xsin4x Solution: Quotient rule of differentiation states that:…

Q: sin3 COs x

A:

Q: sin 0 1- cos 0 = 2 csc 0 1 cos 0 ite the left side of the expression with sin 0(1- cos ) EGO

A: We can establish the identity as asked in the question as below

Q: Sin 5 X

A: We have I = ∫sin-1 5x dx

Q: sin³0 14. lim 0→0 sin0-tan 8

A: To find: The limit of limθ→0sin3θsin θ-tan θ. Formula used: Trigonometric relation: tan θ=sin θcos θ…

Q: Sin² x-sin x-2=0

A:

Q: sin20 6. ) lim tan³0 0- 4

A: Given: limθ→π4sin2θtan3θ

Q: sin 0 What is the value of lim 0→0 0 if 0 is measured in degrees?

A: Given,          limθ→0sinθθ

Q: sin(X)=3/5, X lies in 1st quadrant. Find tan(X)

A:

Q: Sin40-ces"O=2 Sin 0-1

A:

Q: expressions in terms of exponen - In(coshx + sinhx) + In(cosh 2- cosh5x + sinh5x

A: Rewrite the following expressions in terms of exponentials, write the final result as simply as you…

Q: sin 9x + sin 7x

A:

Q: sin 'x) in terms of first powers of cosine.

A:

Q: Find the limit

A: Given limit is Dividing both numerator and denominator by x, we get

Q: sin 4x2 lim 1 cos 6x

A:

Q: Find the limit.

A: Make two parts of the expression. And distribute the limit with both parts as shown:

Q: (Sin X-cos X)^2=1-sin 2x

A: Formulae to note: (a-b)2=a2+b2-2ab. 2 sin x cos x=sin2x. Sin2x+Cos2x=1.

Q: Sin 2X 2. X 3 tan 2X

A: Equating the first derivative of a function to zero and solving the equation for the variable will…

Q: ∫sin(1/x8)dx/x9

A: We have to evaluate the integral: ∫  sin1x8dxx9 This integral will be solved by substitution method…

Q: sin(5x) е. lim х>0 sin(3x)

A:

Q: - sin( - a) + sin-x 元 Simplify sin sin(21- x) 지+ 2

A: Given: sinπ2−x+sin(π−x)+sin3π2−x+sin(2π−x)

Q: sin(5æ) lim when x is measured in degrees. sin(5æ) lim (Give your answer accurate to at least 0.01.)

A: The objective of the question is evaluate the limit of the function.

Q: sin 7x 9. lim 9.h x→0 sin 3x

A: GIVEN limx→0sin7xsin 3x

Q: Find the limit.

A: Evaluate: limx→0 sin 4xsin 6x

Q: sin(3x)-sin x - cot(2x)= cos(3x) - cos x

A:

Q: lim n sin (- n

A:

Q: cosx/1+sinx - 1-sinx/cosx = 0

A:

Q: Sin (3 x) Sin (3 x) dx

A:

Q: sin2x-sinx=0 What are the two ways to solve this?

A:

Q: evaluate the limit.

A:

Q: sin(4.x) Find lim 1-0 tan(2x)

A:

Q: sinx- sin 2x=0

A: Given

Q: [sin(3x) sin(7x) dx a.

A: