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- How did you get from 1+cos2x to 1+cos2x-sin2x? How did you get from 4cos(x/2) to -2(1+cosx)? How did you get from 1+cosx-since to 2cos2x?Does the tangent x cancel itself out? What does the last step say? I can’t read itFind all solutions of 4sin^2xtanx−tanx= 0 that are in the interval [0,2π)When I subtract, I get 2/1-cos2x. How do they get -2cos x/1 - cos2 x?
- how can 2sin(2β)cos(4β) be expressed as a sum?show that cos 6x = cos 2x (4cos2 2x-3)Prove that 1.) 1+sec^2\theta \sin ^2\theta =\sec ^2\theta 2.) \frac{sin\theta }{1-cos\theta }+\frac{1-cos\theta }{sin\theta }=2csc\theta 3.)1+\frac{1}{sin\theta }=\frac{tan^2\theta }{sec\theta -1} 4.) \frac{1}{sec^2\theta }+\frac{1}{csc^2\theta }=1 5.) \frac{1+sin\theta }{sin\theta }=\frac{cot^2\theta }{csc\theta -1} 6.) cos^2\theta +\sin ^2\theta \cos ^2\theta =1