sin- (V302 + 4)

Q: 3. sin 3x sin4 Vx

A: Thanks for the question :)And your upvote will be really appreciable ;)

Q: sec² 0 de tan² 0 – 1

A: Integrate the integral.

Q: 5 sec2(0) de tan(0)

A: let I=∫5sec2(θ)tan(θ)dθ

Q: Rang of : cosx - sinx

A: (2)

Q: 1-sin'(플-x)

A: The objective is to simplify the expression.

Q: 6. sec (sin-1 x)

A: Interconversion

Q: Sec'x 16-tanx

A: Since you have asked multiple questions in a single request so we will be answering only first…

Q: sin(20) 0 = /-

A: When theta is between 0 to 360 degrees, then 2theta is between 0 to 720 degrees. We use sin inverse,…

Q: tan2 θ- sec2 θ =_________

A: To evaluate: tan2θ-sec2θ Solution: We have an identity: sec2θ-tan2θ=1 Therefore,…

Q: sin( sec = (x/10))

A: Let sec-1x10=α ⇒sec α=x10 ⇒sin α=x2-100x⇒α=sin-1x2-100x

Q: sin (-) 3.

A: Given data is: tan5π4 To find the value of tan5π4

Q: ∫〖sin〗^3 xdx

A: Consider the indefinite integral ∫sin3x dx. To solve this integral first rewrite the integrand using…

Q: 2 sin-√3 = 0, [0°, 360°) 2

A:

Q: 2. sin3 350at

A: Given, ft=sin3350at So, the given function can be written as, ft=sin3350at=14-sin3×350at+3sin350at…

Q: sin 4

A:

Q: - Sin (x-꼭)+| %3D

A:

Q: cos2x- sin2x cos2x F(x)+C: What is Fx)? For dr = - 3 cosx - sinx

A: A detailed solution is given below

Q: sin-1

A:

Q: sin 3n 3"

A:

Q: tan2θ - sec2 θ =..............

A: The trigonometric identity is given by: sec2θ=1+tan2θ

Q: sin(2 tan " (-} ))

A: Given,  sin2tan−1−83Formula→2tan−1x=sin−12xx2+1                 sinsin−1x=x

Q: sin(-3x) dx

A: This question can be solved using the concept of integration by substitution

Q: sin(105°)

A: Given :sin( 105 )

Q: ]sin¬' (§) 77

A: Given : The equation is 6 sin2 x + 1 sin x - 1 = 0 and interval [ 0, 2π ) .

Q: Sin sec" 3. 2.

A: (1) We have to evaluated sinsec−1−23 Use he following identity  sinsec−1x=1−1x2

Q: sec(2) tan(2) – 1 dz 3.

A:

Q: Sin (플-) sec(-x) =

A: To solve sin[(π/2)-x] sec(-x)

Q: integrate sin2x/sin5x.sin3x

A: To integrate: ∫sin2xsin5xsin3xdx Solution: We know, sin(A-B)=sinAcosB-cosAsinB    ...(1)…

Q: sin 17° %3D

A: Given sin 17° = ?

Q: sin -4x y =

A: I provided you with two solutions. because the question is not clear. There is confusion in the…

Q: sin aX

A:

Q: sin-1 (-금).

A: Explanation of the solution is given below...

Q: 1. - sin 0 2

A:

Q: ) Write sin(2 sin-(3x)) in terms of x only. (i) 6x/1 – 9x² (ii) 6x (iii) V1 – 9x² - (iv) Not listed

A:

Q: sin -1

A: NOTE: Refresh your page if you can't see any equations. . use the formula

Q: sin 3x = 2 Osx< 2n

A: Answer :- Option C is Correct answer.

Q: tan x 3. = sin x %3D secx

A: “Since you have posted multiple questions, we will solve first question for you. To get remaining…

Q: sin tan - Vx² + 1

A:

Q: csc² x+sec² x 1 cos² sin² 10

A: As we know from the trigonometric identity: 1). sinx=1cscx 2). cosx=1secx 3). sin2x+cos2x=1   Given:…

Q: sin-(x) V1- r2 4.

A:

Q: sinh- x = In 2.

A:

Q: sin'(-x) = - SI

A:

Q: sin2x cos3x dx=- sin5xdx - sinxdx A) True В False

A:

Q: cosx Show that J-3(x) = -. + sinx)

A:

Q: Sin13*

A:

Q: cos2 x(sec2 x - 1)

A: we know that secx=1/cosx. and the identity sin^2x+cos^2x=1.

Q: sin +x + sin = 1 - x-

A:

Q: sec² x 12. S 1+tanx

A: here we use       ddxtanx=sec2x see below the calculation and answer s