Since, F is bounded both in LOR) and in lIR), it is Latnded in LLIR) forall fe[1,0) (Prdtem 31).

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter1: Fundamentals
Section1.2: Mappings
Problem 11E: For the given f:ZZ, decide whether f is onto and whether it is one-to-one. Prove that your decisions...
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the extension oPerator of Theore m 8.6
Therefore Fis bounded in i(R)and also in
Since F is bounded both in LOR) and in LilIR), it is
Solve problem number 31
we Prove that H has a CompPact closure in.
Proof of (7)
Let
ct H be the unit ball in wTd: Let P be
he extension oPerator of Theore m 8.6
and set F=P(H),so that H=F;"
LE(I) (for atl 1<9 c00) bj apPlying Theorem 4-26-
1,1
Clearly, F is bounded in w(R), because
1,1
W CR)
CH, C, for some Ć
1,1
W (R)
(I) m.
La (I) by using (5).
Lounded in LLIR) forall ge[1,0) (Prdtem 31).
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Transcribed Image Text:the extension oPerator of Theore m 8.6 Therefore Fis bounded in i(R)and also in Since F is bounded both in LOR) and in LilIR), it is Solve problem number 31 we Prove that H has a CompPact closure in. Proof of (7) Let ct H be the unit ball in wTd: Let P be he extension oPerator of Theore m 8.6 and set F=P(H),so that H=F;" LE(I) (for atl 1<9 c00) bj apPlying Theorem 4-26- 1,1 Clearly, F is bounded in w(R), because 1,1 W CR) CH, C, for some Ć 1,1 W (R) (I) m. La (I) by using (5). Lounded in LLIR) forall ge[1,0) (Prdtem 31). Scanned with CamScanner
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