Since sin O O tan 1/12 = 1-cos 8 1+cos 0 1 Cos 0 2 " as tan 1-cos 0 tan/2 = √ 1+cos 0 COS /= ± √ || sin COS ONDE 1+cos 0 2
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- How did you get from 1+cos2x to 1+cos2x-sin2x? How did you get from 4cos(x/2) to -2(1+cosx)? How did you get from 1+cosx-since to 2cos2x?Does the tangent x cancel itself out? What does the last step say? I can’t read itSolve sin(4x)cos(8x)−cos(4x)sin(8x)=−0.2sin(4x)cos(8x)-cos(4x)sin(8x)=-0.2 for the smallest positive solution.Find all primary solutions of sin(4x)cos(x) - cos(4x)sin(x)=1