Since the simplified numerator, >0 for all X, we have "(x) > 0 x²-1>0 e ]x > and f"(x) < 0 X| < Thus the curve is concave upward on the intervals (- -1) and and concave downward on It has no point of inflection since 1 and are not in the domain of f

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter2: Working With Real Numbers
Section2.9: Dividing Real Numbers
Problem 9MRE
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413x"+
\)
(X+1\° (メ-113
Transcribed Image Text:413x"+ \) (X+1\° (メ-113
Since the simplified numerator,
>0 for all x, we have
f"(x) > 0 x? - 1 > 0 O
and f"(x) < 0 A x| <
Thus the curve is concave upward on the intervals (- -1) and
and concave downward on
It has no point of inflection since 1 and
are not in the domain of f
Transcribed Image Text:Since the simplified numerator, >0 for all x, we have f"(x) > 0 x? - 1 > 0 O and f"(x) < 0 A x| < Thus the curve is concave upward on the intervals (- -1) and and concave downward on It has no point of inflection since 1 and are not in the domain of f
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