sinny -limy-→1 у-1

Q: lim (4x – 3y)= -11 Prove that (r.,v(-2,1)"

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Q: lim In (z\x2 + y²) P - (5, 5, 1)

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Q: 1 1 lim v→s(vー5 ビ-25 v² - 25, 2 lim w→ -1- 1-w W-3

A:

Q: lim a'/z 2-

A: Given:

Q: lim 1. m, n > 1 is

A: We try to find the limit by substitution

Q: 2cosh (z) – z- z2 lim 24 12 1 3 1 12

A:

Q: ze" – In(1+#) lim

A: To evaluate the given limit.

Q: 22 -y2 =? lim (z,1) (0,0) +y? O A. 0 O B. 1 OC. -1 D. Does not exist Reset Selection

A: Explanation of the answer is as follows

Q: Find the limits

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Q: 10. lim( +1-V +1-)

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Q: 2. lim o -Væ+1°

A: Follow the next step

Q: lim 17) P - (5, 5, 1) In (z\x2 + y²)

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Q: z? +1 lim z4-1 %3D i O -i o

A:

Q: 1) limy-o 2ytan(1/y) sin(r-0²) 2) lim2n 101-Va 2 3) limg-n/2 (n²-482 )sec\ß] tan2x 4) lim T

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Q: z² + iz lim z3 + 1 z- ob ||

A: We are given : limz→∞z2+izz3+1=limz→∞z2+izz3z3+1z3=limz→∞1z+i1z21+1z3=0+i(0)1+0=0…

Q: tan- 2 Evaluate the following: limy- o(2 – x)

A:

Q: limy 2 X- 2

A: Here we have to evaluate limx→21x-12x-2

Q: lim zta sec z is A B 2 D nonexistent

A: Given query is to find value of the limit.

Q: 10. lim Ve+ 2-2

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Q: lim (VI+z- VF),

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Q: lim (2,y)→(1,0) X + y – 1 Determine which of the following paths is not valid to check the existence…

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Q: lim -3- tan-() = lim-otan-ly %3D True False

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Q: lim (2,y,2)(-1,2,-3) 2x – 4y - 3z = -1. %3D

A: Given, lim(x,y,z)->(-1,2,-3) 2x-4y-3z = -1

Q: z+3 lim- %3D iz Z+2

A:

Q: secy-1 Lim seczy-1 a) as y → 0 b) as y – → 1/2

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Q: EXAMPLES. Observe that iz +3 lim z→-1 z +1 z +1 =D0 since lim %3D z→-1 iz + 3

A: Now, limz→-1z+1iz+3=-1+1i(1)+3                 =0-1+3                 =0…

Q: limtt 2→e 2"+そ+ 2- limit (22+1)(2-1) 2っ2 -22+4

A: See the attachment

Q: (2n+1)!+(2n+2)! )! (2n+3 lim

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Q: A = lim %3D i = 1

A: Given that: The equation is f(x) = x 2 e x  ,     0 ≤x≤3 .

Q: 6n + 2 3. n→∞ 2n + 1 3. Using the definition (i.e. N, E), prove that lim

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Q: Find the linearization of y = ev7x at x = 16. (Use symbolic notation and fractions where needed.)

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Q: lim cob lo) -の

A: Given : limθ→-∞cosθ3θ

Q: 16+y limy-o

A: The given function is 16+yy-4y. Simplify the given function as follows.…

Q: lim (2,y)+(0,0) In(2 + x² + y?) x2 + y?

A: We have to solve given limit:

Q: sinny -limy-1 y-1

A: Given, limy→1 sinπyy-1   We have to evaluate the limit.

Q: lim (x,y)→(0,0) (3 + (x² + y²) In(x² + y´

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Q: ANS: (d) |z - 3| lim 243- 12 6 - ANS: -

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Q: Solve z4-1 lim z→i z-i

A: The given expression is: limz→iz4-1z-i

Q: iz° + 1) lim z→-i\ z² 2 +1,

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Q: lim (2,1) (0,0) (1 + (x² + y²) In(2² + y²))

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Q: lim (1,4) (0,0) x2 + y2 Prove that

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Q: limf(z) =lim %3D O صواب İhi O

A: Ans : true

Q: I-1 lim I→1+ Vr²–1

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Q: lim (z,y)→(0,0) (2+(x² +y²) In(x² + y²))

A: We have to find the limit of: lim(x,y)→(0,0) 2+(x2+y2)ln(x2+y2)

Q: 1. lim 目 2+1 is 2.

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Q: If f(x) = xcosx then limf(x+h)-f(x) h COSX = ? %3D %3D h-0

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Q: 1 (iii) lim I-bt 6 – x

A:

Quadratic Equation

When it comes to the concept of polynomial equations, quadratic equations can be said to be a special case. What does solving a quadratic equation mean? We will understand the quadratics and their types once we are familiar with the polynomial equations and their types.

Demand and Supply Function

The concept of demand and supply is important for various factors. One of them is studying and evaluating the condition of an economy within a given period of time. The analysis or evaluation of the demand side factors are important for the suppliers to understand the consumer behavior. The evaluation of supply side factors is important for the consumers in order to understand that what kind of combination of goods or what kind of goods and services he or she should consume in order to maximize his utility and minimize the cost. Therefore, in microeconomics both of these concepts are extremely important in order to have an idea that what exactly is going on in the economy.