sin(x) 1+ 2x Problem 3. We can find the Maclaurin series for f(x) by multiplying the Maclaurin 1 series for sin(x) and 1+ 2x Up to the third order terms, the Maclaurin series for these functions are 1 sin(x) = x - +... 6. and 1– 2.x + 4x? – 8x + ... %3D I+25 = sin(x) 1+ 2x Multiply the two series given above to find the Maclaurin series for f(x) up to third-order terms. In other words, if sin(x) = a + Bx + yx² + 8x³ 1+ 2x +... is the Maclaurin series for f, what are the constants a, B, y, and 8?

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