Situation V: The azimuths of the back and forward tangents (measured from North) of a simple curve respectively are 257 25' and 294°05'. A line with bearing N 69°22'E intersects the forward tangent at a point 28.086 meters from the point of tangency of the simple curve and the simple curve at point Z. (Use arc basis) 10. If the long chord of the simple curve is 120.147 meters and stationing of the vertex is at station 50+134, what would be the stationing of point Z and PT? 11. Determine the length of the curve. 12. Determine the length of the middle ordinate. (Round off your answers to three decimal places)

Situation V: The azimuths of the back and forward tangents (measured from North) of a simple curve respectively are 257 25' and 294°05'. A line with bearing N 69°22'E intersects the forward tangent at a point 28.086 meters from the point of tangency of the simple curve and the simple curve at point Z. (Use arc basis) 10. If the long chord of the simple curve is 120.147 meters and stationing of the vertex is at station 50+134, what would be the stationing of point Z and PT? 11. Determine the length of the curve. 12. Determine the length of the middle ordinate. (Round off your answers to three decimal places)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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