Sketch the region that corresponds to the given inequalities. 2x + 4y 2 20 ys 5 x2 0, y 2 0 y y y 10 10 15 15 10 10 Solution Set Solution Set Solution Set + Isolution Set -10 -5 10 -15 -10 -5 10 15 -15 - 10 -5 10 15 -10 -5 10 -5 -5 -5 -5 -10 -10 10 -15 -15 10 Say whether the region is bounded or unbounded. O The region is bounded. O The region is unbounded. Find the coordinates of all corner points (if any). (Order your answers from smallest to largest x, then from smallest to largest y. If an answer does not exist, enter DNE.) (х, у) - (х, у) - (x, y) =
Sketch the region that corresponds to the given inequalities. 2x + 4y 2 20 ys 5 x2 0, y 2 0 y y y 10 10 15 15 10 10 Solution Set Solution Set Solution Set + Isolution Set -10 -5 10 -15 -10 -5 10 15 -15 - 10 -5 10 15 -10 -5 10 -5 -5 -5 -5 -10 -10 10 -15 -15 10 Say whether the region is bounded or unbounded. O The region is bounded. O The region is unbounded. Find the coordinates of all corner points (if any). (Order your answers from smallest to largest x, then from smallest to largest y. If an answer does not exist, enter DNE.) (х, у) - (х, у) - (x, y) =
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.3: Systems Of Inequalities
Problem 15E
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Step 1
Since x5 and y5, so second and third graph cannot be the required region because in second one shaded region is above y=5 and in third one the shaded region is to the right of x=5.
Substitute 0 for x and y in the first inequality to decide the region.
In the obtained inequality is false, so the region is the one that do not contain the origin.
Hence , first graph is the correct option.
The region is bounded
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