So dt = 1+14 A. B. C. 11/12 71 N|T (x²) arctan (x4) arctan ½ ln (1 + x ¹ )

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter9: Real Numbers And Right Triangles
Section9.7: The Tangent Ration
Problem 14E
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t
So dt:
=
1+t²4
A.
B.
C.
D.
E.
½arctan (x²)
arctan (x4)
In (1+x¹)
-In
(1+2¹)
arcsin (x²)
Transcribed Image Text:t So dt: = 1+t²4 A. B. C. D. E. ½arctan (x²) arctan (x4) In (1+x¹) -In (1+2¹) arcsin (x²)
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