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So we found that the slope of the tangent line at x = 36 is and that (36, 6) is a point on the line. 12 Substituting these values into the point-slope formula y – Yo = m(x - x), we have %3D y-Yo = m(x – x) %3! 1 y – 6 = (x – 36). 12 Solving this for y, we can conclude that the equation of the tangent line to f(x) = x at x = 36 is y = 3.5

So we found that the slope of the tangent line at x = 36 is and that (36, 6) is a point on the line. 12 Substituting these values into the point-slope formula y – Yo = m(x - x), we have %3D y-Yo = m(x – x) %3! 1 y – 6 = (x – 36). 12 Solving this for y, we can conclude that the equation of the tangent line to f(x) = x at x = 36 is y = 3.5

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...
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Step 4 1 and that (36, 6) is a point on the line. 12 So we found that the slope of the tangent line at x = 36 is Substituting these values into the point-slope formula y – y, = m(x - x,), we have y – Y, = m(x - x,) y-6: (x – 36). 12 Y. Solving this for y, we can conclude that the equation of the tangent line to f(x) = vx at x = 36 is %3D Y = 3.5 | Submit Skip (you cannot.come back)
Transcribed Image Text:Step 4 1 and that (36, 6) is a point on the line. 12 So we found that the slope of the tangent line at x = 36 is Substituting these values into the point-slope formula y – y, = m(x - x,), we have y – Y, = m(x - x,) y-6: (x – 36). 12 Y. Solving this for y, we can conclude that the equation of the tangent line to f(x) = vx at x = 36 is %3D Y = 3.5 | Submit Skip (you cannot.come back)
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