SOLUTION: A vector equation of the circular helix is R(t) = a cos ti + a sin tj + tk So D,R(t) =-a sin ti + a cos tj + k and |D,R(t)|= Va +1. From (3) we get T(t) = Vat + (-a sin ti + a cos tj + k) NSIONAL SPACE AND SOLID ANALYTIC GEOMETRY So D,T(t) = VI (-a cos ti – a sin tj) Applying (8), we obtain K(t) a² +1 (-a cos ti -- a sin tj) The curvature, then, is given by K(t) = |K(t)| = and so the curvature of the circular helix is constant. From (11) we get N(t) =-cos ti – sin tj Applying (12), we have B() = VT (-a sin ti + a cos tj + k) × (-cos ti – sin tj) Va? +1 1 Va + 1 (sin ti – cos tj + ak) - COS
SOLUTION: A vector equation of the circular helix is R(t) = a cos ti + a sin tj + tk So D,R(t) =-a sin ti + a cos tj + k and |D,R(t)|= Va +1. From (3) we get T(t) = Vat + (-a sin ti + a cos tj + k) NSIONAL SPACE AND SOLID ANALYTIC GEOMETRY So D,T(t) = VI (-a cos ti – a sin tj) Applying (8), we obtain K(t) a² +1 (-a cos ti -- a sin tj) The curvature, then, is given by K(t) = |K(t)| = and so the curvature of the circular helix is constant. From (11) we get N(t) =-cos ti – sin tj Applying (12), we have B() = VT (-a sin ti + a cos tj + k) × (-cos ti – sin tj) Va? +1 1 Va + 1 (sin ti – cos tj + ak) - COS
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.5: Polar Coordinates
Problem 98E
Related questions
Question
100%
Please show the complete solution on the highlighted part on how they arrived such solution for an upvote. Ty!
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage