solution for this equations are4х1 - 3х2 + х3 - х4 + 2х5 -хб-8х1- Зx2 + х3 -2х4 + х5-2х6 %3D 9-2х1 + 3x2 - х3 + x4- х5 + 2х6 %3D -72х1 + x2 - Зх3 + х4 - 2х5 + 5х6 %3D 2х1 - 2х2 + х3 - Зx4 + х5 -4х6 %3D 45x1 -4х2 - х3- х4 + 4x5 + 5хб — 9%3DSelect one:a. x1-1,x2-2,х3-6,x4-3,х5--4,х6-3b. x1%3-1,x2--2,x3-6,х4-3,x5--4,хб-3с. X1-1,x2--2,х3-6,x4-3,x5-4,хб-3d. x1-1,x2--2,x3-6,x4-3,x5--4,х6-3

We need to find the solution of linear equation of order 6.

solution for this equations are 4x1- 3х2 + х3- х4 + 2х5-хб-8 x1 - 3x2 + x3 - 2x4 + x5 - 2x6 = 9 -2x1 + 3x2 - x3 + x4 - x5 + 2x6 = -7 2x1 + x2 - 3x3 + x4 - 2x5 + 5x6 = 2 х1- 2x2 + х3 -Зx4 + х5 -4х6 %3D 4 5x1 -4x2 - x3 - x4 + 4x5 + 5x6 = 9 Select one: a. x1-1,x2-2,х3-6,x4-3,x5--4,х6-3 b. x1=-1,x2=-2,x3=6,x4=-3,x5=-4,x6=3 C. X1=1,x2=-2,x3=6,x4=-3,x5=4,x6=3 d. x1=1,x2=-2,x3=6,x4=3,x5=-4,x6=3

solution for this equations are 4x1- 3х2 + х3- х4 + 2х5-хб-8 x1 - 3x2 + x3 - 2x4 + x5 - 2x6 = 9 -2x1 + 3x2 - x3 + x4 - x5 + 2x6 = -7 2x1 + x2 - 3x3 + x4 - 2x5 + 5x6 = 2 х1- 2x2 + х3 -Зx4 + х5 -4х6 %3D 4 5x1 -4x2 - x3 - x4 + 4x5 + 5x6 = 9 Select one: a. x1-1,x2-2,х3-6,x4-3,x5--4,х6-3 b. x1=-1,x2=-2,x3=6,x4=-3,x5=-4,x6=3 C. X1=1,x2=-2,x3=6,x4=-3,x5=4,x6=3 d. x1=1,x2=-2,x3=6,x4=3,x5=-4,x6=3

Algebra: Structure And Method, Book 1

(REV)00th Edition

ISBN:9780395977224

Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Chapter2: Working With Real Numbers

Section2.9: Dividing Real Numbers

Problem 10MRE

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