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Solution Given that, boto] (19 ·X43 1-9/3 › X73 F(x) = f(x) = 1/² F(x) = 20. XL3 cx @PIXEN)= P(OLX200) = 10 f(x) dx x=3 = [² 27 dx = 27 X 27X+ 81 27 X4 -3 1 f(x) = 81 x ²3 xt = 3 = 1/2 #1 Therefore, given put is not valid bat because I flxdx#1 Now. making valid pdf by multiplying 3, we get, * x=-1 Apien I 7 (6) P (52X²7) = √" f(x) dx x=5 =81 X73 = 81 X 81 dx X+ 0[*²] 5 1 + 1 1029 375 P(54X27) = 0.1373/ T Answer

Solution Given that, boto] (19 ·X43 1-9/3 › X73 F(x) = f(x) = 1/² F(x) = 20. XL3 cx @PIXEN)= P(OLX200) = 10 f(x) dx x=3 = [² 27 dx = 27 X 27X+ 81 27 X4 -3 1 f(x) = 81 x ²3 xt = 3 = 1/2 #1 Therefore, given put is not valid bat because I flxdx#1 Now. making valid pdf by multiplying 3, we get, * x=-1 Apien I 7 (6) P (52X²7) = √" f(x) dx x=5 =81 X73 = 81 X 81 dx X+ 0[*²] 5 1 + 1 1029 375 P(54X27) = 0.1373/ T Answer

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 5T
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To find P(X>E(X)) first we find the E(x)ie CO E(X)= √ x f(x) dx x=-6 √x B1 3 X4 81 dx = 81[= ²70 = 81 [ + ] 9 =4.5 2 E(X) = Now. P(x > 4-5) = f(x) dx ✓ X=4,5 81 dx = 4.5 x4 jos 81 [23³] 0 x -3 14:5 nakuin stand bited Powe =81/273.375 Ledam pd [4 P(x24.5) = 0.2963, Answer
Transcribed Image Text:To find P(X>E(X)) first we find the E(x)ie CO E(X)= √ x f(x) dx x=-6 √x B1 3 X4 81 dx = 81[= ²70 = 81 [ + ] 9 =4.5 2 E(X) = Now. P(x > 4-5) = f(x) dx ✓ X=4,5 81 dx = 4.5 x4 jos 81 [23³] 0 x -3 14:5 nakuin stand bited Powe =81/273.375 Ledam pd [4 P(x24.5) = 0.2963, Answer
Solution - Given that, fou (vt in T 2 20 .X43 F(x) = 1- f(x) = a dx 오 d. F(x)= X3 = › X7,3 @PIXEN)= P(OLX200) = 100 f(x) dx x=3 SO 27 = Į dx -3 B - 27 [1²³] 30 0. XL3 27 x4 27x11 81 = 1/32 #1 ㅎ = Therefore given pdf is not valid bat because of(x) dx #1 Now. making valid pdf by multiplying 3, we get, x= X=-1 √ I f(x) = 81₁ x ²3 7 P ( 5 ≤ x² 7) = √ + f(x) dx x=5 X73 =81 781 dx X+ = 81 / x²-377 5 +1 1029 375 P(52X47) = 0.1373) Answer KA-MANTA
Transcribed Image Text:Solution - Given that, fou (vt in T 2 20 .X43 F(x) = 1- f(x) = a dx 오 d. F(x)= X3 = › X7,3 @PIXEN)= P(OLX200) = 100 f(x) dx x=3 SO 27 = Į dx -3 B - 27 [1²³] 30 0. XL3 27 x4 27x11 81 = 1/32 #1 ㅎ = Therefore given pdf is not valid bat because of(x) dx #1 Now. making valid pdf by multiplying 3, we get, x= X=-1 √ I f(x) = 81₁ x ²3 7 P ( 5 ≤ x² 7) = √ + f(x) dx x=5 X73 =81 781 dx X+ = 81 / x²-377 5 +1 1029 375 P(52X47) = 0.1373) Answer KA-MANTA
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