Solution in JS Taking each four digit number of an array in turn, return the number that you are on when all of the digits 0-9 have been discovered. If not all of the digits can be found, return "Missing digits!". Examples findAllDigits ([5175, 4538, 2926, 5057, 6401, 4376, 2280, 6137, 8798, 9083]) 5057 // digits found: 517- 4-38 29-6 -0
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- # the method take another circular array and returns a linear array containing the common elements between the two circular arrays. def intersection(self, c2): # To Do print("==========Test 10==========") lin_arr9 = [10, 20, 30, 40, 50, None, None, None] c10 = CircularArray(lin_arr9, 5, 5) c10.printFullLinear() # This should print: 40, 50, None, None, None, 10, 20, 30 lin_arr10 = [5, 40, 15, 25, 10, 20, 5, None, None, None, None, None] c11 = CircularArray(lin_arr10, 8, 7) c11.printFullLinear() # This should print: 10, 20, 5, None, None, None, None, None, 5, 40, 15, 25 output = c10.intersection(c11) print(output) # This should print: [10, 20, 40]given an array of integer values , return true if 6 appears as either the first or last element in the array. firstLast6([1,2,36]) true firstLast([6,1,2,3]) true firstLast([13,6,1,2,3]) falseInstrument shellsort to print the number of compares divided by the array sizefor each increment. Write a test client that tests the hypothesis that this number is asmall constant, by sorting arrays of random Double values, using array sizes that areincreasing powers of 10, starting at 100
- public static void reverseAscendingSubarrays(int[] items) Rearrange the elements of the given array of integers in place (that is, do not create and return a new array) so that the elements of every maximal strictly ascending subarray are reversed. For example, given the array {5, 7, 10, 4, 2, 7, 8, 1, 3}, after executing this method, the elements of the array would be {10, 7, 5, 4, 8, 7, 2, 3, 1}. Given another argument array {5, 4, 3, 2, 1}, the contents of that array would stay as {5, 4, 3, 2, 1} seeing that its each element is a maximal ascending subarray of length one. public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire…Given a sorted array of n integers that has been rotated an unknownnumber of times, write code to find an element in the array. You may assume that the array wasoriginally sorted in increasing order.EXAMPLElnput:find5in{15, 16, 19, 20, 25, 1, 3, 4, 5, 7, 10, 14}Output: 8 (the index of 5 in the array)Given a sorted array of n integers that has been rotated an unknownnumber of times, write code to find an element in the array. You may assume that the array wasoriginally sorted in increasing order.EXAMPLElnput:find5in{15, 16, 19, 20, 25, 1, 3, 4, 5, 7, 10, 14}Output: 8 (the index of 5 in the array Given a sorted array of n integers that has been rotated an unknownnumber of times, write code to find an element in the array. You may assume that the array wasoriginally sorted in increasing order.EXAMPLElnput:find5in{15, 16, 19, 20, 25, 1, 3, 4, 5, 7, 10, 14}Output: 8 (the index of 5 in the array
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- Suppose that you are playing a card game whose goal is to collect exactly k cards with a total value of t. Write a solution that can determine if it is possible for a given collection of cards whose values are given in the array values. For example, if the array contained the values <10,5,7,2>, k = 3, and t = 12, you would return false because no three values add to 12. However, if t = 14, you would return true, since 5 + 7 + 2 = 14. So I considered this to be a form of groupSum recursion, so I try to implement it in recursion form. However, since the passing parameters are not the incrementing level index but 'k' that is the limit number of the numbers we can choose from the array, I cannot use passing index through recursion to search from the start of the array toward the end of the values.length(the length of the array). would there be any method I can use to increment and search along the array using k, the number of numbers we can add into the total(t) instead of the…Can you make the array be randomly genorated instead of already named values, and ask the user to enter the number of numbers that will be genorated in the array. Everything else can stay the same. '''def binary_search(arr, x): low = 0high = len(arr) - 1mid = 0while low <= high: mid = (high + low) // 2if arr[mid] < x: low = mid + 1elif arr[mid] > x: high = mid - 1else: return mid return -1arr = [ 2, 3, 4, 10, 40 ] print("The array is [ 2, 3, 4, 10, 40 ]")x = int(input("Enter which value do you seek to find from the array above? "))while not (x==2 or x==3 or x==4 or x == 10 or x == 40):print("Option isn't in the array.")x = int(input("Please input a valid number to search "))result = binary_search(arr, x) print("Searching for", x) if result != -1: print("Element is present at index", str(result))Why does this return an empty array and not 'G','H','I','J','K','B' x = ['A','B','C','D','E','F','G','H','I','J','K',]k = x[6:1]print(k)