Solve: 4(x – 5) = 2x – 14. 4x – 20 = 2r 14 - | 4x 2x - 20 = 2x 2x – 14 2x 20 = -14 2x 20 + 20 -14 + 20 2x = 6 2x 2 2 x = 3 Checking gives -8 = -8, so 3 is the solution, or {3} is the solution set.
Solve: 4(x – 5) = 2x – 14. 4x – 20 = 2r 14 - | 4x 2x - 20 = 2x 2x – 14 2x 20 = -14 2x 20 + 20 -14 + 20 2x = 6 2x 2 2 x = 3 Checking gives -8 = -8, so 3 is the solution, or {3} is the solution set.
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter9: Systems Of Linear Equations
Section9.2: The Substitution Method
Problem 12WE
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