Solve: 6x3 + 12x = 17x2 This equation is not quadratic, because it contains a term involving x. However, we can solve it by using factoring. First we get 0 on the right side by subtracting 17x2 from both sides. Then we factor the polynomial on the left side and use an extension of the zero-factor property. To use the zero-factor property, we need one side of the equation to be factored completely and the other side to be 0. 6x3 + 12x = 17x² 6x3 -Ox2 + 12x = 17x² – 17x² This is the equation to solve. To get 0 on the right side, subtract 17x2 from both sides. 6x3 – 17x2 + 12x = 0 Combine like terms: 17x2 – 17x² = 0. x(6x2 – 17x + ) = 0 Factor out the GCF, x. x(2x – -| )(3x – 4) = 0 Factor the trinomial, 6x² – 17x + 12. If x(2x – 3)(3x – 4) = 0, then at least one of the factors is equal to 0. x = 0 or 2x - 3 = 0 or 3x -O= 0 Set each factor equal to 0. 2x = X= 4 Solve each equation. X = The solutions are 0, 3/2, and 4/3 and the solution set is {0, 4/3, 3/2}. Check each solution in the original equation, 6x3 + 12x = 17x2. Solve: 10x3 – x² = 2x X = (smallest value) X = | (largest value) %3D
Solve: 6x3 + 12x = 17x2 This equation is not quadratic, because it contains a term involving x. However, we can solve it by using factoring. First we get 0 on the right side by subtracting 17x2 from both sides. Then we factor the polynomial on the left side and use an extension of the zero-factor property. To use the zero-factor property, we need one side of the equation to be factored completely and the other side to be 0. 6x3 + 12x = 17x² 6x3 -Ox2 + 12x = 17x² – 17x² This is the equation to solve. To get 0 on the right side, subtract 17x2 from both sides. 6x3 – 17x2 + 12x = 0 Combine like terms: 17x2 – 17x² = 0. x(6x2 – 17x + ) = 0 Factor out the GCF, x. x(2x – -| )(3x – 4) = 0 Factor the trinomial, 6x² – 17x + 12. If x(2x – 3)(3x – 4) = 0, then at least one of the factors is equal to 0. x = 0 or 2x - 3 = 0 or 3x -O= 0 Set each factor equal to 0. 2x = X= 4 Solve each equation. X = The solutions are 0, 3/2, and 4/3 and the solution set is {0, 4/3, 3/2}. Check each solution in the original equation, 6x3 + 12x = 17x2. Solve: 10x3 – x² = 2x X = (smallest value) X = | (largest value) %3D
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section9.6: Solving Quadratic Equations By Using The Quadratic Formula
Problem 58HP
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