3) solve the circle using Using System of linear equation solution :-atV1412super mode.~2 { + +1}mode V2.22wwwV8-VIV1 + VI-V2 + V8-V₂2230v(+2-1 + 2-32-V2 + V3VI+V2 -V3V₂V3-V1 = 30= 803V1 -V2 +4V222Solve equationwww15 AV1 = 30v60vV3 = 60v+-VB{{}}6V8V2 + 5 V3 = 015= 15- V1 +2 V2 -V3 = 30V38√2AmpIF+ V398= 0=0(2)(3)tsolvelitusingSystemof linear eq

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Answered: Solve equation V1 = 30V V2 = 60v V3 =…

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Electrical Engineering

Solve equation V1 = 30V V2 = 60v V3 = 60V 12 ar 3 Am tsolve lit using System of Katar eq

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.61P

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Question

3) solve the circle using Using System of linear equation

solution :-
at
V1
412
super mode.
~2 { + +1}
mode V2.
22
www
V8-
VI
V1 + VI-V2 + V8-V₂
2
2
30v
(+
2-1 + 2-3
2
-V2 + V3
VI+V2 -V3
V₂
V3-V1 = 30
= 80
3V1 -V2 +
4
V2
22
Solve equation
www
15 A
V1 = 30v
60v
V3 = 60v
+
-VB{{}}
6V8V2 + 5 V3 = 0
15
= 15
- V1 +2 V2 -V3 = 30
V3
8√2
Amp
IF
+ V3
98
= 0
=0
(2)
(3)
tsolve
lit
using
System
of linear eq

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