Solve FG only • In the following problems solve the value of internal force member in thetruss using the method of Section.• Show the free body diagram (FBD) or the cut portion of your truss.• Solving without any FBD in your solution is considered wrong.• State whether each member is in TENSION (T) or COMPRESSION (C) Prob. 13 - 181.2 kN1.04 kN ' kN1.24 kN1 kN1.04 kN1.24 kN|0.6 kN0.6 kN1.75 m2.87 mD4.80 m3.68 mPAXC|EHKM3.84 m|3.6 m3.84 m2.4 m 3.6 m 3.6 m 2.4 m3.6 m13. FG =14. EG =15. ЕН -16. КМ -17. LM =18. LN =

Support reaction: Due to symmetry:AY=12×(2×(0.6+1.24+1.04+1)+1.2)=4.48 KN

Answered: Solve FG only

Engineering

Civil Engineering

Solve FG only

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Connections

In steel structures, connections are the members that join two or more steel members. The connections are the most important members of any steel structure, and hence, they are designed more carefully. The majority of the construction cost of steel structures is incurred due to the connections. The design of connections is done as per the recommendations and specifications of the American Institute of Steel Construction (AISC).

Question

Solve FG only

• In the following problems solve the value of internal force member in the
truss using the method of Section.
• Show the free body diagram (FBD) or the cut portion of your truss.
• Solving without any FBD in your solution is considered wrong.
• State whether each member is in TENSION (T) or COMPRESSION (C)

Prob. 13 - 18
1.2 kN
1.04 kN ' kN
1.24 kN
1 kN
1.04 kN
1.24 kN
|0.6 kN
0.6 kN
1.75 m
2.87 m
D
4.80 m
3.68 m
P
AX
C|
E
H
K
M
3.84 m|
3.6 m
3.84 m
2.4 m 3.6 m 3.6 m 2.4 m
3.6 m
13. FG =
14. EG =
15. ЕН -
16. КМ -
17. LM =
18. LN =

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