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Solve for: 1. Current Al: uA 2. Voltage Vout: V 3. Gain =

Solve for: 1. Current Al: uA 2. Voltage Vout: V 3. Gain =

Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter18: Resistive-inductive Parallel Circuits
Section: Chapter Questions
Problem 13PP: In an R-L parallel circuit, IT=1.25 amps, R=1.2k, and XL=1k. Find IR
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In the circuit is a circuit that is only a little different to the one in the course notes, it has an extra resistor across the input V*. a non-inverting an inverting OpAmp -1.829V Vout R1 56k2 R3 180KO R2 150kO If we want to analyse this circuit, we need to know what effect that resistor has on the circuit. Let's begin with what you have been taught about circuit theory. The Vin and V+ are on the same node there is no resistance between them, and therefore the voltage on V* is -1.829 V. So, the resistor has no effect on our analysis. You see that R3 and R2 form a voltage divider - but how can we know this? What about the input V' of the OpAmp, wont it have an effect? The key is that there is no current into V- as the input resistance of an OpAmp inputs is on. This means all the current through R3 will go through R2, so it will have no effect on the voltage divider and can be excluded from our model. This means we can redraw the circuit like this. R2 V- R3 Vout (=Vin) OV Solve for: 1. Current A1: uA 2. Voltage Vout: 3. Gain =|
Transcribed Image Text:In the circuit is a circuit that is only a little different to the one in the course notes, it has an extra resistor across the input V*. a non-inverting an inverting OpAmp -1.829V Vout R1 56k2 R3 180KO R2 150kO If we want to analyse this circuit, we need to know what effect that resistor has on the circuit. Let's begin with what you have been taught about circuit theory. The Vin and V+ are on the same node there is no resistance between them, and therefore the voltage on V* is -1.829 V. So, the resistor has no effect on our analysis. You see that R3 and R2 form a voltage divider - but how can we know this? What about the input V' of the OpAmp, wont it have an effect? The key is that there is no current into V- as the input resistance of an OpAmp inputs is on. This means all the current through R3 will go through R2, so it will have no effect on the voltage divider and can be excluded from our model. This means we can redraw the circuit like this. R2 V- R3 Vout (=Vin) OV Solve for: 1. Current A1: uA 2. Voltage Vout: 3. Gain =|
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