Solve for GS: (D⁴+5D+4)y = cos (3x+4)

Q: y Ct) = 5e - 2t Cos 67 fCt) = 3c 4t C1- 3t + 2t 2) -4t (1- 3t + 2t²)

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Q: cos z) dz 4 5.

A: Given: - The indefinite integral is, ∫e2zcos14zdz To find: - The solution of the given integral.

Q: - sin² ydy 6. 4 tan" y

A: As per the guidelines I can solve only first question

Q: Solve: Tanxdy+ y°Sin²xdx=0, y(0)=1 а. у"(3-Сos2x)-2 b. у(-2х + Сos2х) -1 d. y(-1+ Cos2x) — х с. у?…

A: This question is related to differential equations, We will solve it using given information.

Q: Solve the given DEQ by undetermined coefficients. y" + y = 2x sin x

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Q: Solve the equation: (D² - 1) y = 0 Oy=c₁e* + c₂xe* + c3 cos x + c4 sinx Oy=c₁e¹* + c₂e + c3 cos x +…

A: A detailed solution is given below.

Q: [xVtan x² sec* x² dx -

A: Given,         ∫xtanx2sec4x2dx

Q: Use Method of Undetermined Coefficients: y" - 2y' + 5y = 4e*cos2x +x2 2

A: We have given a differential equation ,  y'' - 2y' + 5y = 4ex cos2x + 52x2 First we will find…

Q: The equation y = C₁e(-x) cos3x + C₂e(-x)sin3x is the general solution of:

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Q: solve using linear (y-cos2x)dx + cosxdy = 0

A: Topic = Differential equation

Q: Solve y"-2y'+ 2y = e* + cosx

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Q: fcos cos² xdx 2.

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Q: Solve: y" - 6y + 15y = 2 sin 2t, y(0) = -1, y'(0) = -4

A: Let's solve given diffrential equation.

Q: Solve y''-2y'+2y=ex+cosx

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Q: : y=cos4x-sin4x

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Q: y=cos(4x) /cos22x-4sin2x cos2x differentiate?

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Q: y= - 2 cos 4x +3

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Q: )xsin(x?) dx

A: The given integral is: ∫0πx sinx2dx To integrate this, consider x2=t  .... (1) On integrating both…

Q: Solve the DE (D-1)y= 3 sinx+ 22 - 2x°2

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Q: Solve the equation: y" + 2y" + y' = 4 sin æ + 18e2

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Q: dy Solve cos2x ty3D tanx

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Q: 6x2 y = 2y + cos y

A: We need to find the derivative of the given function

Q: Solve the general solution y'=cos2x cosy

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Q: 1 x³ y =e*(dsin²3x-tanx ) - 10 y'=? (fх +1)

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Q: Q: Solve y+8= Cos (x) ナ3sin(2x)

A: Given: y''+y=cos x+3 sin 2xCE: m2+1=0⇒m=±iCF: e(0)x( Acos x +B sin x)=Acos x +B sin x

Q: Solve by the method of y" +3y' - 4y = - 34 cos x

A: Given, y"+3y'-4y= -34cos x

Q: d 5s- Cos-3 s(s*- 1st1)

A: We use partial fraction method to decompose given function of s and then use inverse Laplace…

Q: +2 y = 3e" cos 2x -2

A: Solution

Q: y= (sec ³x + tan ²x)

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Q: d²y + y = 4 cos x dx² Please solve this equation by hypothesis (V)

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Q: Solve  y′ + 2y cos(2t) = 2 cos(2t), y(π/2 ) = 0

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Q: Solve (D² - 2D + 5) y = sin (2x) + 17x cos (2x) — 15x -

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Q: sec?x - dx |1- 4tan²x 1 –

A: We will solve this question using simple Integration formulae.

Q: (D² – 3D+2)y= sin3x

A: We will find out the required general solution.

Q: () x² cos ,2 dx 3.

A: Given problem:-

Q: Ssin8 (3z) cos5 (3z) dz

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Q: What is the midline equation of y = -4 sin (2x-7)+3?

A: Given y=- 4 sin (2x-7)+3

Q: Solve (D2+9)y=cos 3x+sin2x

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Q: cos(x) 2x+3

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Q: Solve(D^2+9)y=cos^3x

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Q: Solve: y" + 9y = 9csc3x O y = C1 cos3x + C2 sin3x – 3xcos3x + sin3xln(sin3x)

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Q: 3x*y+2x +y² +5 = cos(2x)+5x

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Q: :.) Solve the equation using discontinuous function: y" + 9y = cos(2t) – u47(t)cos(2t)

A: Please check step 2 for the solution.!

Q: Find a value of x that satisfies the equation sec (-316°) = csc (x, %3D

A: Given: sec(-316°)=cscx We know that sec90°-x=cscx

Q: 6) y = cos-1 (9x2 – 4) V1 + (9x2 – 4)2 -18x C) V1 - (9x2 – 4)2

A: Given function, y=cos-19x2-4

Q: Cos(-) Xdx Sx2

A: Given: 5.∫cos1x5x2dx 6.∫x2-4x2dx

Q: solve the equation cos2x = cos x for -π ≤ x ≤ π.

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Q: Solve f 8x cos(7x) dx using Integration by Parts.

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Q: Write the general solution(s): 2 cos(x-) = -

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