Solve for the higher order DE number 2

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Conic Sections
Section8.2: More Parabolas And Some Circles
Problem 63.2PS: By expanding (xh)2+(yk)2=r2, we obtain x22hx+h22ky+k2r2=0. When we compare this result to the form...
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Solve for the higher order DE number 2

(D7 + D° – 2D5 – 2D4 – 7D³ – 7D² – 4D – 4) y = 0
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(D4 – 3D3 + 4D)y = 6 + 80cos2x
y" + 4y' + 3y = sin (e*)
%3D
Transcribed Image Text:(D7 + D° – 2D5 – 2D4 – 7D³ – 7D² – 4D – 4) y = 0 | (D4 – 3D3 + 4D)y = 6 + 80cos2x y" + 4y' + 3y = sin (e*) %3D
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