Solve for the value of constant(C) by obtaining the orthogonal trajectory of the given equation below.4y2=ax“a” is an arbitrary constantSolve of “C” @ x=1. y=2 Solve for the value of constant(C) by obtaining the orthogonal trajectory of the given equation below.4y2-ax"a" is an arbitrary constantSolve of "C" @ x=1. y=2

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Answered: Solve for the value of constant(C) by…

Solve for the value of constant(C) by obtaining the orthogonal trajectory of the given equation below. 4y2-ax "a" is an arbitrary constant Solve of "C" @ x=1. y=2

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Dimensional homogeneity

The term dimensional homogeneity means that in an equation, the dimensions of each term on both sides are equal, which means the dimensions of the left-hand side (LHS) of an equation are similar to the dimensions of the right-hand side (RHS). For a dimensionally homogeneous equation, the powers of fundamental dimensions will be identical on both sides of the equation.

Question

Solve for the value of constant(C) by obtaining the orthogonal trajectory of the given equation below.

4y²=ax

“a” is an arbitrary constant

Solve of “C” @ x=1. y=2

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