Question
Asked Nov 8, 2019
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Solve for x log (30x+20)- log(x)=2

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Expert Answer

Step 1
The given price equation is log (30x+20)-log (x)
2.
Solve the equation for x as follows
log (30x +20)-log (x)= 2
log (30x 20)-log(x)+log (x)= 2+ log (x)
log(30x +20) 2+1log (x)
log (30x +20) log (10)+ log (x)
log (30x +20) log (100)+ log (x)
(Add log (x) on both sides)
(2=log(10))
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The given price equation is log (30x+20)-log (x) 2. Solve the equation for x as follows log (30x +20)-log (x)= 2 log (30x 20)-log(x)+log (x)= 2+ log (x) log(30x +20) 2+1log (x) log (30x +20) log (10)+ log (x) log (30x +20) log (100)+ log (x) (Add log (x) on both sides) (2=log(10))

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