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SOLVE IT AS NEW DONT SPAM SOLUTION FROM ANOTHER QUESTIONS TY. Using a table similar to that shown in Figure 3.10, calculate 35 divided by 11 using the hardware described in Figure 3.8. You should show the contents of each register on each step. Assume both inputs are unsigned 6-bit integers.

SOLVE IT AS NEW DONT SPAM SOLUTION FROM ANOTHER QUESTIONS TY. Using a table similar to that shown in Figure 3.10, calculate 35 divided by 11 using the hardware described in Figure 3.8. You should show the contents of each register on each step. Assume both inputs are unsigned 6-bit integers.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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SOLVE IT AS NEW DONT SPAM SOLUTION FROM ANOTHER QUESTIONS TY.

Using a table similar to that shown in Figure 3.10, calculate 35 divided by 11
using the hardware described in Figure 3.8. You should show the contents of
each register on each step. Assume both inputs are unsigned 6-bit integers. 

Iteration Step Quotient Divisor Remainder 0000 0111 0110 0111 Initial values 0000 0010 0000 1: Rem = Rem - Div 0000 0010 0000 2b: Rem < 0= +Div, sll Q. Q0 = 0 3: Shift Div right 1 0000 0010 0000 0000 0111 0000 0001 0000 0000 0111 1: Rem = Rem – Div 0000 0001 0000 0111 0111 2b: Rem <0= +Div, sll Q. Q0 = 0 3: Shift Div right 2 0000 0001 0000 0000 0111 0000 0111 0111 1111 0000 0000 1000 1: Rem = Rem - Div 0000 0000 1000 2b: Rem <0 +Div, sll Q. Q0 = 0 3: Shift Div right 3 0000 0000 1000 0000 0111 0000 0000 0100 0000 0111 1: Rem = Rem - Div 0000 0000 0100 @o00 0011 2a: Rem 20= sll Q. Q0 =1 3: Shift Div right 4 0001 0000 0100 0000 0011 0001 0000 0010 0000 0011 1: Rem = Rem – Div 0001 0000 0010 Co00 0001. 2a: Rem 20= sll Q. Q0 = 1 0011 0000 0010 0000 0001 3: Shift Div right 0011 0000 0001 0000 0001 FIGURE 3.10 Division example using the algorithm in Figure 3.9. The bit examined to determine
Transcribed Image Text:Iteration Step Quotient Divisor Remainder 0000 0111 0110 0111 Initial values 0000 0010 0000 1: Rem = Rem - Div 0000 0010 0000 2b: Rem < 0= +Div, sll Q. Q0 = 0 3: Shift Div right 1 0000 0010 0000 0000 0111 0000 0001 0000 0000 0111 1: Rem = Rem – Div 0000 0001 0000 0111 0111 2b: Rem <0= +Div, sll Q. Q0 = 0 3: Shift Div right 2 0000 0001 0000 0000 0111 0000 0111 0111 1111 0000 0000 1000 1: Rem = Rem - Div 0000 0000 1000 2b: Rem <0 +Div, sll Q. Q0 = 0 3: Shift Div right 3 0000 0000 1000 0000 0111 0000 0000 0100 0000 0111 1: Rem = Rem - Div 0000 0000 0100 @o00 0011 2a: Rem 20= sll Q. Q0 =1 3: Shift Div right 4 0001 0000 0100 0000 0011 0001 0000 0010 0000 0011 1: Rem = Rem – Div 0001 0000 0010 Co00 0001. 2a: Rem 20= sll Q. Q0 = 1 0011 0000 0010 0000 0001 3: Shift Div right 0011 0000 0001 0000 0001 FIGURE 3.10 Division example using the algorithm in Figure 3.9. The bit examined to determine
Divisor Shift right 64 bits Quotient Shift left 64-bit ALU 32 bits Remainder Control Write test 64 bits FIGURE 3.8 First version of the division hardware. The Divisor register, ALU, and Remainder
Transcribed Image Text:Divisor Shift right 64 bits Quotient Shift left 64-bit ALU 32 bits Remainder Control Write test 64 bits FIGURE 3.8 First version of the division hardware. The Divisor register, ALU, and Remainder
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