Solve the differential equation [cos (2y) - 3x²y²] dx + [cos (2y) - 2x sin (2y) — 2x³y] dy = 0 - a. sin (y) cos (y) - x cos (2y) x³y² = C - b. cos (2y) + x cos (2y) - 2x³y² = C c. sin (y) cos (y) + x cos (2y) - x ³ y ² = d. sin (2y) + 2x cos (2y) — 2x³y² = C C

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