Solve the differential equation [x a. b. C. d. y tan ¹()] 2x tan-¹(²) -¹ (²/2) dx + x tan¯¹ (²/2)dy = 0 |c²(x² + y²) 24 2y tan-¹(²) = x ln -1 2x tan-¹ () = x ln x In c² (x² + y²) y4 | c² (x² + y²) 2y tan-¹() = x ln c² (x²+y²) |

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