Solve the differential equation xy' - 2y = 6x? In x. Put the equation into standard form, y' + P(x)y = Q(x). To put the given equation into standard form, divide by x to obtain 2 2 y'-y = 6x In x, so that P(x) = To solve the linear equation, y' + P(x)y = Q(x), multiply both sides by the integrating factor P(x)dx and integrate both sides. v(x) = Now find the integrating factor v(x) = JWA, where P(x) = - so v(x) is as simple as possible. Use a constant of integration C X dx v(x) = e = e - 2 In x Multiply through by v(x) = 1 (6x In x). How? 2 6 In x Simplify to obtain The form of the equation becomes (v(x) • y) = v(x)Q(x). dx Now the left side is dx y so integrate both sides to obtain = 3( In x) + Cwhere C is the constant of integration

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Please attached image for question. I cant figure out how it uses the equation to obtain solution. Please show steps on how the solution is achieved. Thank you for the help.

Now find the integrating factor v(x) = eJ'W, where P(x) = -
Solve the differential equation xy' - 2y = 6x In x.
Put the equation into standard form, y' + P(x)y = Q(x).
To put the given equation into standard form, divide by x to obtain
2
2
y' -y = 6x In x, so that P(x) =
To solve the linear equation, y' + P(x)y =Q(x), multiply both sides by the integrating factor
P(x)dx
and integrate both sides.
v(x) =
Padk where P(x)=
Now find the integrating factor v(x) =
Use a constant of integration C = 0,
so v(x) is as simple as possible.
dx
v(x) = e
= e
-2 In x
Multiply through by v(x) =-
1
(6x In x).
How?
2
6 In x
Simplify to obtain
The form of the equation becomes (v(x) • y) = v(x)Q(x).
dx
Now the left side is
dx
so integrate both sides to obtain
= 3( In x) + C where C is the
constant of integration.
Finally, multiply both sides of the equation by x? to obtain y = 3x2( In x)? + Cx2.
Transcribed Image Text:Now find the integrating factor v(x) = eJ'W, where P(x) = - Solve the differential equation xy' - 2y = 6x In x. Put the equation into standard form, y' + P(x)y = Q(x). To put the given equation into standard form, divide by x to obtain 2 2 y' -y = 6x In x, so that P(x) = To solve the linear equation, y' + P(x)y =Q(x), multiply both sides by the integrating factor P(x)dx and integrate both sides. v(x) = Padk where P(x)= Now find the integrating factor v(x) = Use a constant of integration C = 0, so v(x) is as simple as possible. dx v(x) = e = e -2 In x Multiply through by v(x) =- 1 (6x In x). How? 2 6 In x Simplify to obtain The form of the equation becomes (v(x) • y) = v(x)Q(x). dx Now the left side is dx so integrate both sides to obtain = 3( In x) + C where C is the constant of integration. Finally, multiply both sides of the equation by x? to obtain y = 3x2( In x)? + Cx2.
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