Solve the equa tion on the interval [ o, 2 ) 2 sin? 9-3 sin O +1 =0 tan2x-1 =0 (2 cos x +JE) (2 sin x +1) = 0 2 cos?x + sin x-1 =D0 X + sin x-1 =0

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 57E
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Solve the equa tion on the interval [o,2)
2 sin? 9-3 sin 0 +1 =D0
tan?x-1 3D0
(2cosx+J3)2 sin x +1) = 0
[0,2
%3D
COs
2.
2 Cos X t sin x-1 D0
Transcribed Image Text:Solve the equa tion on the interval [o,2) 2 sin? 9-3 sin 0 +1 =D0 tan?x-1 3D0 (2cosx+J3)2 sin x +1) = 0 [0,2 %3D COs 2. 2 Cos X t sin x-1 D0
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