Solve the equation for θ, where 0 ≤ θ ≤ 2π.   2 sin2 = 1

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section: Chapter Questions
Problem 27RE
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Solve the equation for θ, where 0 ≤ θ ≤ 2π.   2 sin2 = 1

Expert Solution
Step 1

To solve equation 2sin2θ=1.

Solving the given equation,

2sin2θ=1sin2θ=12sinθ=±12

Now,

sinθ=12θ=sin-112θ=π4,3π4 

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