Solve the equation for all degree solutions and if 0° ≤ ? < 360°. Do not use a calculator. (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.) 2 cos theta - root 3 = 0 a) all degree solutions (Let k be any integer.) b)  0° ≤ ? < 360°

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A: Use the double angle formula as follows.

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A: Here, the given equation is: 2cos(2x) cos(x)-2sin(2x) sin(x)=1⇒cos(2x) cos(x)-sin(2x)…

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A: By using properties of trigonometry

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A: We need to find the three small positive values of x.

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A: we use the formula sin2x=2sinx cosx . see 2nd step.

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A: Given:    cos2(x) - 2 cos(x) - 3 = 0 , x belong to [ 0 , 2π )

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A: Given: 2sinxcos2x+2cosxsin2x=-32; x∈[0,2π) we know that sinAcosB+cosAsinB=sinA+B…

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Q: solutions

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A: Given that, the equation is cos2θ-π2=1 and θ∈0,2π. 2θ-π2=cos-112θ-π2=0+2nπ That is, 2θ-π2=0+2nπ.

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A: The trigonometric identity for sine and cosine is sin2x+cos2x=1.