Solve the equation for solutions in the interval [0, 2). Use algebraic methods and give exact values. sin() = √√3 - sin(). The Solution set is T {₁ 39 2л 4л 5л 39 39 3 °{#, #} 2π 39 3

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 56E
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Solve the equation for solutions in the interval [0, 2).
Use algebraic methods and give exact values.
sin() = √√3 - sin().
The Solution set is
{₁
T
39
2л 4л 5л
39 39 3
{#, #}
2π
39
3
Transcribed Image Text:Solve the equation for solutions in the interval [0, 2). Use algebraic methods and give exact values. sin() = √√3 - sin(). The Solution set is {₁ T 39 2л 4л 5л 39 39 3 {#, #} 2π 39 3
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