Solve the equation, where 0° < x < 360°. Round approximate solutions to the nearest tenth of a degree. (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.) 2 sin x cos x - V3 sin x - 2 cos x + V3 = 0 X =

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.2: Trigonometric Equations
Problem 60E
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3.6, q.14 PLEASE ANSWER THE QUESTION, MAKE SURE THE ANSWER IS CORRECT, BOX THE ANSWER, MAKE THE ANSWER EXACTLY AS IT SHOULD BE IN THE TEXT BOX PLEASE!!

Solve the equation, where 0° < x < 360°. Round approximate solutions to the nearest tenth of a degree. (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.)
2 sin x cos x - V3 sin x - 2 cos x + V3 = 0
X =
Transcribed Image Text:Solve the equation, where 0° < x < 360°. Round approximate solutions to the nearest tenth of a degree. (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.) 2 sin x cos x - V3 sin x - 2 cos x + V3 = 0 X =
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