Solve the following 3 quadratic equationsusing the quadratic formula:-b±yb²–4ac2aa) 4x2 + 12x + 9 = 0b) x² – x + 3 = 0-c) 2x2 + 5x – 2 = 0Cd) The value under the radical(6² – 4ac) is called the discriminant.Using the examples that you calculatedabove, explain how the discriminantdetermines how many real solutions thereare for a quadratic equation.

a) 4x2+12x+9=0 a=4 , b=12 , c=9 x=-12±(12)2-4(4)(9)2(4) =-12±144-1448 =-12±08…

Solve the following 3 quadratic equations using the quadratic formula: -b±yb²-4ac 2а a) 4x² + 12x + 9 = 0 6) x² – x + 3 = 0 %3D c) 2x2 + 5x – 2 = 0 d) The value under the radical (62 – 4ac) is called the discriminant. | Using the examples that you calculated above, explain how the discriminant determines how many real solutions there are for a quadratic equation.

Solve the following 3 quadratic equations using the quadratic formula: -b±yb²-4ac 2а a) 4x² + 12x + 9 = 0 6) x² – x + 3 = 0 %3D c) 2x2 + 5x – 2 = 0 d) The value under the radical (62 – 4ac) is called the discriminant. | Using the examples that you calculated above, explain how the discriminant determines how many real solutions there are for a quadratic equation.

College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter1: Equations And Graphs

Section: Chapter Questions

Problem 15CC

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