Question
Asked Oct 3, 2019
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solve the following initial value problem.

dr/dθ= -πcos πθ, r(2)=3

(Type an exact answer, using π as needed.)

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dr -T COS(T) with initial Consider the given first order differential equation as de condition r(2) = 3 Solve the initial value problem by separating the variable as follows πcos( πθ) dθ dr =-cos(n0)de (Integrate both sides) r -sin Te C r =-sin r0 +C

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Tagged in

Math

Calculus

Differential Equations