Solve the given differential equation 5x4cos 2 ydx - dy = 0 (A) y = tan-¹ (x5 + C) B) y=x5+ C C y = tan (x³ + C)

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Chapter1: Functions And Models
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15.
Solve the given differential equation.
5x 4cos 2 ydx - dy = 0
(A) y = tan-¹ (x5 + C)
B) y=x5 + C
(C) y = tan (x5 + C)
D) y = tan-¹ (x4 + C)
Transcribed Image Text:Solve the given differential equation. 5x 4cos 2 ydx - dy = 0 (A) y = tan-¹ (x5 + C) B) y=x5 + C (C) y = tan (x5 + C) D) y = tan-¹ (x4 + C)
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