Question

Asked Nov 19, 2019

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Solve the given system:

m_{1}x_{1}''=-k_{1}x_{1}+k_{2}(x_{2}-x_{1})

m_{2}x_{2}''=-k_{2}(x_{2}-x_{1})

when k_{1}=3, k_{2}=2, m_{1}=1, m_{2}=1 and

x_{1}(0)=0, x_{1}'(0)=1, x_{2}(0)=1, x_{2}'(0)=0

x_{1}(t)=

x_{2}(t)=

Step 1

It is given that, the system and the initial conditions are,

Step 2

Substitute the initial conditions as,

Step 3

The first order system o...

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