Solve the initial value problems in Exercises 139–142. dy 139. dx x² + 1 y(1) = -1 (*+ !)'. dy y(1) = 1 140. - dx d²r 141. dr? 3 r'(1) = 8, r(1) = 0 Vi 15Vi + %3D d³r = -cos t, r"(0) = r'(0) = 0, r(0) = -1 142. dt3

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