Question
Asked Nov 12, 2019
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Solve the polynomial inequality:

3x2+x<2(x+2)

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Expert Answer

Step 1

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3x? +х<2(х+2)

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Step 2

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3x +х<2х + 4 Зx? +х- 2х-4 <2х+4-2х-4 3x —х -4<0 3x? -4х +3х-4 <0 x(3х - 4) + (3х - 4) <о (3х -4)(х+1) <0 3х — 4 <0 or х+1<0 4 or x- х<

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