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Solve the problem. Supply and demand functions, S(X) and D(X), are given for a particular commodity in terms of the level of production X. In each case: S(X) = 4x + 250 and D(X) = -6x + 480 a. For what values of x is there a market shortage? b. For what values of x is there a market surplus? O a. 0 23 a. 0 342 O a. x> 23; b. 0 342; b. 0

Solve the problem. Supply and demand functions, S(X) and D(X), are given for a particular commodity in terms of the level of production X. In each case: S(X) = 4x + 250 and D(X) = -6x + 480 a. For what values of x is there a market shortage? b. For what values of x is there a market surplus? O a. 0 23 a. 0 342 O a. x> 23; b. 0 342; b. 0

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section9.9: Combining Functions
Problem 50HP
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Solve the problem. Supply and demand functions, S(X) and D(X), are given for a particular commodity in terms of the level of production X. In each case: S(X) = 4x + 250 and D(X) = -6x + 480 a. For what values of x is there a market shortage? b. For what values of x is there a market surplus? O a. 0<x< 23; b. x> 23 O a. 0<x< 342; b. x> 342 a. x> 23; b. 0 <x< 23 a. x>342; b. 0 <x< 342
Transcribed Image Text:Solve the problem. Supply and demand functions, S(X) and D(X), are given for a particular commodity in terms of the level of production X. In each case: S(X) = 4x + 250 and D(X) = -6x + 480 a. For what values of x is there a market shortage? b. For what values of x is there a market surplus? O a. 0<x< 23; b. x> 23 O a. 0<x< 342; b. x> 342 a. x> 23; b. 0 <x< 23 a. x>342; b. 0 <x< 342
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