Solve triangle ABC if ZA = 36.8°, a = 186.2, and b = 246.3. sin B = (round answer to 5 decimal places) There are two possible angles B between 0° and 180° with this value for sine. Find the two angles, and report them so that ZB1 is the acute angle. ZB¡ = and ZB2 = (round these and all remaining answers to 1 decimal place) Thus, two triangles satisfy the given conditions: triangle A, B1C, and triangle A,B2C2. Solve the first triangle: A, B1C1 ZC1 = and ci = Solve the second triangle: A2 B2C2 ZCz and c2

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